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直接解答：计算x的x次方的导数，我们可以通过链式法则和对数求导法。令y = x^x，首先取自然对数，得到lny = x * ln (x)。对两边关于x求导，得到dy/dx = (lny)' = (x*lnx)'，进一步计算得dy/dx = ln (x) + 1。因此，x的x.
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